Final answer:
The question asks for the temperature corresponding to the given rms speed of carbon dioxide molecules, which can be solved by applying the formula for rms speed in an ideal gas and rearranging the equation to solve for temperature in Kelvin.
Step-by-step explanation:
The question involves the concept of the root-mean-square (rms) speed of gas molecules, which is a topic in Physics, specifically in the area of thermodynamics and kinetic theory. To find the temperature that corresponds to the given rms speed for a molecule with a known molar mass, we would use the formula:
Urms = \(\sqrt{(3k_BT/M)}\)
Where Urms is the root-mean-square speed, k_B is Boltzmann's constant (1.38 \(\times\) 10-23 J/K), T is the temperature in Kelvin, and M is the molar mass in kilograms per mole.
To find T, we rearrange the equation to:
T = \(\frac{M \cdot Urms^2}{3k_B}\)
First, we convert the molar mass of carbon dioxide from grams per mole to kilograms per mole:
M = 44.0 g/mol \(\times\) 1 kg/1000 g = 0.044 kg/mol
Next, we can plug the known values into our rearranged equation:
T = \(\frac{0.044 kg/mol \cdot (1.05 \(\times\) 10^5 m/s)^2}{3 \cdot 1.38 \(\times\) 10^{-23} J/K}\)
Upon solving, this will give us the temperature in Kelvin. Remember to use appropriate significant figures based on the given data.