Sure. Here are the steps on how to solve the equation 3|x + 1| ≥-6:
Divide both sides of the equation by 3.
Simplify both sides of the equation.
Isolate x on the left-hand side of the equation.
Test each solution in the original equation to make sure it makes the equation true.
Write the solution in interval notation.
Here are the detailed steps:
Divide both sides of the equation by 3:
3|x + 1| ≥-6
|x + 1| ≥ -2
Simplify both sides of the equation:
|x + 1| ≥ -2
x + 1 ≥ -2 or x + 1 ≤ -2
Isolate x on the left-hand side of the equation:
x + 1 ≥ -2
x ≥ -2 - 1
x ≥ -3
x + 1 ≤ -2
x ≤ -2 - 1
x ≤ -3
Test each solution in the original equation to make sure it makes the equation true.
Test x = -3 in the original equation:
3|-3 + 1| ≥-6
3|-2| ≥-6
3(2) ≥-6
6 ≥-6
True
Test x = -4 in the original equation: