The value of the spring constant of this spring will be 50,000 N/m, which has a equilibrium length of 0.100m applied by 40N force.
Step-by-step explanation:
Formula for the spring force is given as- F = (1/2) kx²
where, F = force, k= spring constant and x = change in length of the spring.
Change in length of the spring = Changed length - equilibrium length
Change in length of the spring(x) = 0.140m - 0.100m = 0.040m Putting the values as F = 40.0 N, x = 0.040m, k =?
F = (1/2) kx²40 = (1/2) × k × (0.040)²k = 80/0.0016k = 50,000 N/m
Therefore, the value of the spring constant of this spring will be 50,000 N/m