Question

How many liters of hydrogen gas is produced at 298 K and 0. 940 atm if 4. 00 moles of hydrochloric acid react with an excess of magnesium metal?

Answer 1

To determine the volume of hydrogen gas produced, we can use the ideal gas law equation:

PV = nRT

Where:
P = Pressure (in atm) = 0.940 atm
V = Volume of hydrogen gas (in liters) (the value we want to find)
n = Moles of hydrogen gas = 4.00 moles (since 1 mole of hydrochloric acid produces 1 mole of hydrogen gas)
R = Ideal gas constant = 0.0821 L·atm/(mol·K)
T = Temperature in Kelvin = 298 K

Rearranging the equation to solve for V, we have:

V = (nRT) / P

Substituting the given values:

V = (4.00 mol * 0.0821 L·atm/(mol·K) * 298 K) / 0.940 atm
≈ 100.94 L

Therefore, approximately 100.94 liters of hydrogen gas would be produced.