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How many different 9-letter

arrangements are possible using
the letters in the word DISAPPEAR?

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(9!)/(2!2!)=(3\cdot4\cdot5\cdot6\cdot7\cdot8\cdot9)/(2)=90720


9! is the number of arrangements of all 9 letters, but since the same letters are indistinguishable, we divide by the number of their permutations. And there are two instances of two different letters, hence
2!2!.

User Swathy Krishnan
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