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2C0(g) + 02(g) -+ 2C02(g) 9. 0 L of O2 react with excess CO at STP. How many moles of CO2 form during the reaction?

User MagikCow
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Answer: 0.80 moles CO2

Explanation: use stoichiometry to solve

9.0 L O2 x (1mole O2 / 22.4 L O2) X (2 mole CO / 1mole O2) =0.80 moles CO2

User Thadeus Ajayi
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