59.3k views
2 votes
PLEASE HELP PLEASE ITS A DEADLINE PLEASE

PLEASE HELP PLEASE ITS A DEADLINE PLEASE-example-1

1 Answer

7 votes

Answer: (4, -1) -- All real numbers -- [-1, ∞) -- (3,0) and (5,0). -- (0,15) -- x = 4 -- y = x^2-8x+15

Explanation:


y = (x-4)^2 - 1

a) Vertex: (4, -1). In a quadratic in vertex form:
(x-h)^2 + k, the vertex is the point (h,k)

b) Domain: Since it is a valid quadratic function, the graph extends for all x values. (in other words, you can plug in any value for x). The domain is thus all real numbers.

c) Range: You can plug in any value for x, but since x is being squared, you wont get every value out, you will only get positives out. But there is another condition; there is a -1 constant trailing the equation. this means the graph is shifted one unit down. thus, the y values, the range, is taken down by one as well. the range is thus all numbers from -1 to ∞, or in interval notation, [-1, ∞)

d) X-intercepts: from the graph we can see the intercepts are (3,0) and (5,0).

e) Also from the graph, the y-intercept can be seen as: (0,15)

f) Axis of Symmetry: It is always the line x = x-coordinate of vertex.

so in this case, the line will be x = 4

g) to find a congruent equation, simply expand this equation:


y = (x-4)^2 - 1


y = x^2-8x+16 - 1


y = x^2-8x+15

there ya go!

PLEASE HELP PLEASE ITS A DEADLINE PLEASE-example-1
User Ann Addicks
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories