Question

what capacitance, in μfμf , has its potential difference increasing at 6.0×105 v/sv/s when the displacement current in the capacitor is 0.80 aa ? express your answer using two significant figures.

Answer 1

The capacitance of the capacitor is 1.33 μF.

Step-by-step explanation:

To find the capacitance of a capacitor when the potential difference is increasing at a certain rate and the displacement current is given, we can use the formula:

C = (I / dV) × 10⁶

where:

• C is the capacitance in microfarads (μF)
• I is the displacement current in amperes (A)
• dV is the change in potential difference in volts (V)

Plugging in the given values:

• I = 0.80 A
• dV = 6.0 × 10⁵ V/s

We can calculate:

C = (0.80 / 6.0 × 10⁵) × 10⁶ = 1.33 μF (rounded to two significant figures)