Answer:
A. Empirical formula => C₂H₄O
B. Molecular formula => C₄H₈O₂
Step-by-step explanation:
From the question given above, the following data were obtained:
Mass of C = 0.273 g
Mass of H = 0.046 g
Mass of O = 0.182 g
Molar mass of compound = 88 g/mol
A. Determination of the empirical formula of the compound.
C = 0.273 g
H = 0.046 g
O = 0.182 g
Divide by their molar mass
C = 0.273 /12 = 0.023
H = 0.046 /1 = 0.046
O = 0.182 /16 = 0.011
Divide by the smallest
C = 0.023 / 0.011 = 2
H = 0.046 / 0.011 = 4
O = 0.011 / 0.011 = 1
Thus, the empirical formula of the compound is C₂H₄O
B. Determination of the molecular formula of the compound.
Empirical formula = C₂H₄O
Molar mass of compound = 88 g/mol
Molecular formula =?
Molecular formula = [C₂H₄O]ₙ
[C₂H₄O]ₙ = 88
[(12×2) + (4×1) + 16]n = 88
[24 + 4 + 16]n = 88
44n = 88
Divide both side by 44
n = 88 / 44
n = 2
Molecular formula = [C₂H₄O]ₙ
Molecular formula = [C₂H₄O]₂
Molecular formula = C₄H₈O₂