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A +6.50 μC point charge is moving at a constant 7.50 ×106m/s in the +y-direction, relative to a reference frame. At the instant when the point charge is at the origin of this reference frame, what is the magnetic-field vector B⃗ it produces at the following points.

Part A
x=0.500m,y=0, z=0
Enter your answers component-wise and numerically separated by commas.
Bx, By, Bz = T

User Chris Cruz
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Final answer:

Without explicit formulas or rules provided by the question, we cannot precisely calculate the magnetic field vector at a specific point due to a moving charge. The direction of the magnetic field would be determined by the right-hand rule, and its magnitude would be related to the charge magnitude, velocity, and distance from the point.

Step-by-step explanation:

To calculate the magnetic field vector produced by a moving charge, we can use the Biot-Savart law or, for point charges, a corresponding derivation from it. However, the information given in the question doesn't provide a direct formula or context for calculating the magnetic field vector B at the given point in space. Typically, for a charge moving in a straight line, we would expect to use a derivation that relates the velocity of the charge, its distance from the point in question, and the charge's magnitude to find the magnetic field.

In such a scenario, the magnetic field would be circular around the direction of the charge's velocity vector and its magnitude determined by the aforementioned factors. However since the question doesn't provide a specific formula or rule to follow, we cannot provide a precise answer. Normally, you would need to invoke the right-hand rule to determine the direction of the magnetic field, which is perpendicular to the plane formed by the velocity of the charge and the vector pointing from the charge to the point of interest.

User Crazy Joe Malloy
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