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Question 8 (1 point)
What is the pressure of a gas that originally occupied 2.7 L at a pressure of 3.4 atm,
if the volume is increased to 10.0 L?
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Urgent help pleasee Question 8 (1 point) What is the pressure of a gas that originally-example-1
User Unblevable
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Answer:

13 atm

Step-by-step explanation:

Ideal gas laws let us calculate different values for gases.

Boyle's Law

One of the ideal gas laws is Boyle's law. Boyle's law states that pressure and volume are inversely proportional. This means that as pressure increases, volume decreases and vice versa. In equation form, Boyle's law is:

  • P₁V₁ = P₂V₂

This means to find the original pressure, all we have to do is plug in the known values and solve for P₁.

Solving for P

Firstly, let's plug in the known volumes and pressure.

  • P₁ * 2.7L = 3.4atm * 10.0L

Then, divide both sides by 2.7 to find the original pressure.

  • P₁ ≈ 12.59 atm

Since this equation is based on measured values, we should round to significant figures. Rounded to 2 sig figs, the original pressure was 13 atm.

User Sergio Flores
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