Answer:
To find the x-intercepts, we need to set y = 0 and solve for x:
2(x + 1)^2 + 3 = 0
2(x + 1)^2 = -3
(x + 1)^2 = -3/2
This equation has no real solutions because the square of any real number is always positive or zero, and -3/2 is negative.
To find the y-intercept, we need to set x = 0:
2(0 + 1)^2 + 3 = 5
Therefore, the y-intercept is (0, 5).