Question

A 0.76 kg ball moves in a circle that is 0.8 m in radius at a speed of 4.3 m/s. Calculate

the centripetal acceleration of the ball.

Answer 1

The centripetal acceleration of the ball can be calculated using the formula:

a = v^2 / r

where

v = 4.3 m/s (speed of the ball)

r = 0.8 m (radius of the circle)

Plugging in the values:

a = (4.3 m/s)^2 / 0.8 m

a = 23.035 m/s^2

Therefore, the centripetal acceleration of the ball is 23.035 m/s^2.

Answer 2

`\huge\boxed{\sf a_c \approx 23.1 \ m/s^2}`

Step-by-step explanation:

Given data:

Mass = m = 0.76 kg

Radius = r = 0.8 m

Speed = v = 4.3 m/s

Required:

Centripetal acceleration =
`a_c` = ?

Formula:

`\displaystyle a_c=(v^2)/(r)`

Solution:

Put the given data in the above formula.

`\displaystyle a_c=((4.3)^2)/(0.8) \\\\\displaystyle a_c=(18.49)/(0.8) \\\\a_c \approx 23.1 \ m/s^2\\\\\rule[225]{225}{2}`