Answer:

Explanation:
Given trigonometric equation:

To solve the equation, begin by factoring out cos²(x) from the left side of the equation:

Apply the zero-product property to create two equations to solve:


Solve cos²(x) = 0:

[To find the solutions using a unit circle, locate the points where the x-coordinate is zero, since each (x, y) point on the unit circle is equal to (cos θ, sin θ).]
Therefore, the solutions on the interval [0, 2π] are:


Solve 2csc(x) - 1 = 0:

As the range of the sine function is -1 ≤ sin(x) ≤ 1, there is no solution for x ∈ R.

Solutions
Therefore, the solutions to the given trigonometric equation on the interval [0, 2π] are:
