Answer: Calculate the Volume of Chlorine Gas (Cl₂) at STP That Will React With 5.00 Grams of Iron.
Step-by-step explanation:
The balanced chemical equation for the reaction between iron and chlorine gas is:
2 Fe(s) + 3 Cl₂(g) → 2 FeCl₃(s)
To calculate the volume of chlorine gas that will react with 5.00 grams of iron, we need to use stoichiometry.
First, we need to convert the mass of iron to moles using its molar mass:
5.00 g Fe × (1 mol Fe / 55.85 g Fe) = 0.0893 mol Fe
Next, we can use the mole ratio between iron and chlorine gas from the balanced equation to find the number of moles of chlorine gas:
0.0893 mol Fe × (3 mol Cl₂ / 2 mol Fe) = 0.134 mol Cl₂
Finally, we can use the ideal gas law to calculate the volume of chlorine gas at STP:
PV = nRT
where P = 1 atm, V is the volume we want to calculate, n = 0.134 mol, R = 0.08206 L·atm/(mol·K), and T = 273 K.
Solving for V:
V = nRT/P = (0.134 mol)(0.08206 L·atm/(mol·K))(273 K)/(1 atm) = 3.44 L
Therefore, the volume of chlorine gas at STP that will react with 5.00 grams of iron is 3.44 L.
{I Hope This Helps! :)}