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Factor 4x^2 - 9 over 6x^2 + 9x
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5 votes
Factor

4x^2 - 9 over 6x^2 + 9x

User Silviu
by
7.9k points

1 Answer

3 votes

Answer:

Original fraction: 4x^2 - 9 / 6x^2 + 9x

Factor 4x^2 - 9: (2x + 3)(2x - 3)

Factor 6x^2 + 9x: 3x(2x + 3)

Divide numerator and denominator by 3x: (2x - 3)/2x

Factored form: (2x - 3)/2x

User Angelos Chalaris
by
7.6k points
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