If 17.36 grams of potassium oxide is actually produced, what is the % yeild of this reaction?

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asked Feb 6, 2024 195k views

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Idriss Eliguene · Answer 1 · 2024-02-10T21:20:10+0000

Assuming that the actual yield of potassium oxide was 17.36 grams, the percent yield would be:

Percent yield = (17.36 g / 471 g) x 100% = 3.68%

This means that only 3.68% of the theoretical yield was actually produced in the reaction.

If 17.36 grams of potassium oxide is actually produced, what is the % yeild of this reaction?

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