Question

a chef is testing out a new iron cookware. He knows that iron specific heat of 445 j/kg Celsius. he heats a 2kg iron pan on a stove for 5 minutes and finds that the temperature of the iron skillet has increased by 150 degrees Celsius. calculate the amount of heat energy absorbed by the pan.

Answer 1

`\boxed {\boxed {\sf 133,500 \ Joules}}`

Step-by-step explanation:

Since we are given the specific heat, mass, and change in temperature, we should use this formula for heat energy.

`q=mc \Delta T`

The mass is 2 kilograms. Iron's specific heat is 445 Joules per kilogram degree Celsius. The temperature increases by 150 degrees Celsius.

`m= 2 \ kg \\c= 445 \ J/kg \textdegree C\\\Delta T= 150 \textdegree C`

Substitute the values into the formula.

`q= (2 \ kg)( 445 \ J/kg \textdegree C)(150 \textdegree C)`

Multiply the first two numbers. The kilograms will cancel.

`q= 890 \ J/\textdegree C (150 \textdegree C)`

Multiply again. This time the degrees Celsius cancel.

`q= 133, 500 \ J`

The pan absorbs 133,500 Joules of heat energy.