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I’m in the middle of taking a refresher homework for calc 2 and need help with this question.

I’m in the middle of taking a refresher homework for calc 2 and need help with this-example-1
User Dezhik
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2 Answers

7 votes

Solution:


z=(ln(36)+5)/(2ln(6)+1) \approx 1.8727

Step-By-Step:

Refer to the attached image, please follow carefully.

I’m in the middle of taking a refresher homework for calc 2 and need help with this-example-1
User Frankline
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4 votes

Answer:

z = (5 + ln 36) / (1 + ln 36)

Explanation:

36 e⁵⁻ᶻ − 6²ᶻ = 0

Add 6²ᶻ to both sides:

36 e⁵⁻ᶻ = 6²ᶻ

Change 36 to 6².

6² e⁵⁻ᶻ = 6²ᶻ

Divide both sides by 6².

e⁵⁻ᶻ = 6²ᶻ / 6²

Use exponent rule.

e⁵⁻ᶻ = 6²ᶻ⁻²

Take natural log of both sides.

ln e⁵⁻ᶻ = ln 6²ᶻ⁻²

Use log rule.

(5 − z) ln e = (2z − 2) ln 6

Simplify and solve.

5 − z = (2z − 2) ln 6

5 − z = (2 ln 6) z − 2 ln 6

5 + 2 ln 6 = (2 ln 6) z + z

5 + 2 ln 6 = (1 + 2 ln 6) z

z = (5 + 2 ln 6) / (1 + 2 ln 6)

You can use log rule to simplify further.

z = (5 + ln 36) / (1 + ln 36)

User Yurii Bondarenko
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