Question

A freight train has a mass of [02] kg. The wheels of the locomotive push back on the tracks with a constant net force of 7.50 × 105 N, so the tracks push forward on the locomotive with a force of the same magnitude. Ignore aerodynamics and friction on the other wheels of the train. How long, in seconds, would it take to increase the speed of the train from rest to 80.0 km/h?

Answer 1

t = 300.3 seconds

Step-by-step explanation:

Given that,

The mass of a freight train,
`m=1.01* 10^7\ kg`

Force applied on the tracks,
`F=7.5* 10^5\ N`

Initial speed, u = 0

Final speed, v = 80 km/h = 22.3 m/s

We need to find the time taken by it to increase the speed of the train from rest.

The force acting on it is given by :

F = ma

or

`F=(m(v-u))/(t)\\\\t=(m(v-u))/(F)\\\\t=(1.01* 10^7* (22.3-0))/(7.5* 10^5)\\\\t=300.3\ s`

So, the required time is 300.3 seconds.