Question

20 POINTS!!!

A spinner has 10 equally sized sections, 3 of which are gray, and 7 of which are blue. The spinner is spun twice. What is the probability that the first spin lands on blue and the second spin lands on gray? Write your answer as a fraction in the simplest form.

Answer 1

7/45.

Explanation:

The probability of getting blue on the first spin is 7/10, since there are 7 blue sections out of a total of 10 sections.

After the first spin, there will be 9 sections left, out of which 2 are gray and 7 are blue. The probability of getting gray on the second spin, given that the first spin was blue, is 2/9, since there are 2 gray sections left out of a total of 9 sections.

To find the probability of both events happening together (getting blue on the first spin and gray on the second spin), we need to multiply their individual probabilities:

(7/10) × (2/9) = 14/90

Simplifying this fraction by dividing both the numerator and denominator by 2, we get:

7/45

Therefore, the probability of the first spin landing on blue and the second spin landing on gray is 7/45.

(reference to chatgpts work)