Question

A bag contains 4 red balls, 3 white balls and 5 green balls. a) If one ball is picked at random, what is the probability that it is not green? b) If two balls are drawn at random without replacement, what is the probability that one is red and the other is white?​

Answer 1

Answer: For Part A, the answer is 7/11 or 0.64 when expressed as a decimal.

For Part B: the answer is 12/121 or .099 when expressed as a decimal.

Explanation:

For Part A you need to calculate the amount of balls, which in this case is 11. Since the question is asking for the probability of NOT picking a green ball, you need to find how many balls are not green, which is 7. In other words the fraction is 7/11

For Part B, you need to find the probability of picking one red and white ball. The fraction for picking a red ball is 4/11 and the fraction for picking a white ball is 3/11. You can multiply them across resulting in the answer being 12/121.

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