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What is the domain
y=\sqrt{25-x^(2)

User Gaetanm
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1 Answer

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Given equation: y = √25 - x^2

The domain of this equation is all real values of x such that √25 - x^2 is defined.

Step 1: Write the equation in terms of x only so that we can identify the domain:

y = √25 - x^2

=> x^2 = √25 - y

=> x = √(√25 - y)

Step 2: Since "√25-y" must be greater than or equal to 0 for the equation to be defined, we can set the inequality to find the domain for x as:

√25 - y ≥ 0

=> -y ≥ -√25

=> y ≤ √25

Therefore, the domain for the equation y = √25 - x^2 is all real values of x such that y is less than or equal to √25. Represented in the standard form of intervals, this can be written as:

Domain: x ∈ (-∞, +∞) and y ∈ [0, √25]

User Vora Ankit
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