Question

Question 8 of 36

A balloon contains 11.1 g of nitrogen monoxide gas (NO). How many
molecules are in the balloon?
The Periodic Table
A. 333 molecules
B. 2.23 x 1023 molecules
C. 6.68 x 1024 molecules
D. 22 molecules

Answer 1

The answer is B. 2.23 * 10^23 molecules.

To solve this problem, we'll use Avogadro's number, which is the number of particles (molecules or atoms) in a mole of a substance:

1 mole = 6.022 x 10^23 particles (Avogadro's number)

First, we need to find the number of moles of NO in the balloon:

11.1 g NO x (1 mol NO / 30.01 g NO) = 0.370 mol NO

Then, we can use Avogadro's number to find the number of molecules in the balloon:

0.370 mol NO x (6.022 x 10^23 molecules NO / 1 mol NO) = 2.23 x 10^23 molecules NO

Therefore, there are approximately 2.23 x 10^23 molecules of NO in the balloon.