Question

7. The points (-1,-5) and (6,-5) are

on a coordinate plane. What is the
distance between the points?
A 5 units
B 7 units
12 units
D20 units

Answer 1

`\huge\boxed{\sf D = 7 \ units}`

Explanation:

Point 1 = (x₁, y₁) = (-1, -5)

Point 2 = (x₂, y₂) = (6, -5)

So,

x₁ = -1

y₁ = -5

x₂ = 6

x₂ = -5

Using distance formula to solve the question.

Solution:

`D=√((x_2-x_1)^2+(y_2-y_1)^2) \\\\D=√((6-(-1))^2+(-5-(-5)^2) \\\\D=√((6+1)^2+(-5+5)^2) \\\\D=√((7)^2+(0)^2) \\\\D=√((7)^2) \\\\D = 7 \ units\\\\\rule[225]{225}{2}`