Question

How many moles of K₂CO3 are in a 150.0 g sample

Answer 1

1.09 mol

Step-by-step explanation:

The mass of K₂CO3 is 138

How

by calculating the individual molecular mass

K₂ + C + O3

= 2(39) + 12 + 3(16)

= 78 + 12 + 48

= 138g

formula for finding mole is

`mole = (given \: mass)/(molar \: mass)`

`mole = (150)/(138)`

mole = 1.0869565217

approximately

mole = 1.09 (2d.p)

i hope this helps

Answer 2

1.08 mol

Step-by-step explanation:

To find the number of moles of potassium carbonate (K2CO3) in a 150.0 g sample, you need to know the molar mass of K2CO3. The molar mass is the mass of one mole of a substance, and it is expressed in grams per mole (g/mol).

The molar mass of K2CO3 is 138.20 g/mol. To find the number of moles in a 150.0 g sample, you can divide the mass of the sample by the molar mass:

Number of moles = mass / molar mass

= 150.0 g / 138.20 g/mol

= 1.08 mol

Therefore, there are 1.08 moles of K2CO3 in a 150.0 g sample.