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What are the solutions to the polynomial equation 27x3−8=0? Please with explanation

User Artworkjpm
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Answer:

Explanation:


27x^3 - 8 = 0\\(3x)^3 - (2)^3 = 0\\(3x - 2)(9x^2 + 6x + 4) = 0\\x = 2/3\\9x^2 + 6x + 4 = 0\\(3x)^2 + 2.3x.1 + 1^2-1^2+4 = 0\\(3x+1)^2 = -3\\×××× Rejected

x = 2/3

User Karren
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