Answer: To solve this problem, we can use the combined gas law:
(P1 * V1) / T1 = (P2 * V2) / T2
where:
P1 = initial pressure (which we can assume is constant)
V1 = initial volume
T1 = initial temperature
P2 = final pressure (which we can assume is constant)
V2 = final volume (what we're trying to find)
T2 = final temperature
We can rearrange this formula to solve for V2:
V2 = (P1 * V1 * T2) / (T1 * P2)
Plugging in the given values:
P1 = P2 = the pressure is assumed to be constant, so we don't need to use this variable
V1 = 258 L
T1 = 78 °C + 273.15 (converting to Kelvin) = 351.15 K
T2 = 122 °C + 273.15 (converting to Kelvin) = 395.15 K
V2 = (258 L * 395.15 K) / (351.15 K)
V2 = 290.6 L (rounded to one decimal place)
Therefore, if the temperature of the nitrogen gas in the container changed from 78 °C to 122 °C, the volume of the gas would increase to approximately 290.6 liters.
Explanation: :)