Answer:
D.) 9:1
he original poster has an area of:
Area = length x width = 5 in x 3 in = 15 sq in
When the length and width are tripled, the new poster has a length of 5 in x 3 = 15 in and a width of 3 in x 3 = 9 in. So, the area of the new poster is:
New Area = length x width = 15 in x 9 in = 135 sq in
The ratio of the area of the new poster to the area of the original poster is:
New Area : Original Area = 135 sq in : 15 sq in = 9 : 1
Therefore, the ratio of the area of the new poster to the area of the original poster is 9:1