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2 NaOH + H₂SO4 → 2 H₂O + Na₂SO4

How many moles of water can be produced from 0.48 moles of sulfuric acid? Answer with sig figs.

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Answer:

The balanced chemical equation for the reaction between sodium hydroxide (NaOH) and sulfuric acid (H₂SO₄) is:

NaOH + H₂SO₄ → 2H₂O + Na₂SO₄

From the equation, we can see that 1 mole of sulfuric acid (H₂SO₄) produces 2 moles of water (H₂O). Therefore, we can use a mole ratio to calculate the moles of water produced.

Mole ratio: 1 mol H₂SO₄ → 2 mol H₂O

Given that you have 0.48 moles of sulfuric acid (H₂SO₄), we can set up the following proportion:

0.48 mol H₂SO₄ / 1 × 2 mol H₂O / 1 mol H₂SO₄

Simplifying the proportion, we find:

0.48 mol H₂SO₄ × (2 mol H₂O / 1 mol H₂SO₄) = 0.96 mol H₂O

Rounding to the correct number of significant figures, we have:

0.96 moles of water (H₂O) can be produced from 0.48 moles of sulfuric acid (H₂SO₄).

Step-by-step explanation:

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