Answer:
The balanced chemical equation for the reaction between sodium hydroxide (NaOH) and sulfuric acid (H₂SO₄) is:
NaOH + H₂SO₄ → 2H₂O + Na₂SO₄
From the equation, we can see that 1 mole of sulfuric acid (H₂SO₄) produces 2 moles of water (H₂O). Therefore, we can use a mole ratio to calculate the moles of water produced.
Mole ratio: 1 mol H₂SO₄ → 2 mol H₂O
Given that you have 0.48 moles of sulfuric acid (H₂SO₄), we can set up the following proportion:
0.48 mol H₂SO₄ / 1 × 2 mol H₂O / 1 mol H₂SO₄
Simplifying the proportion, we find:
0.48 mol H₂SO₄ × (2 mol H₂O / 1 mol H₂SO₄) = 0.96 mol H₂O
Rounding to the correct number of significant figures, we have:
0.96 moles of water (H₂O) can be produced from 0.48 moles of sulfuric acid (H₂SO₄).
Step-by-step explanation: