Question

A two-dimensional array is used to represent a matrix. The declaration is below: int(1) matrix = new int[2][3]; public static void changeMatrix (int[matrix) for (int y = 0; y< matrix.length; y++) for (int x = 0; x< matrixtyl.length; x++) if y) matrix[y1x) = Math.abs(matrixty) (x)} If matrix is initialized to be: [(-1. 2. 31.(4.-5, 6]]. What will the values in matrix be after changeMatrix(matrix) is called? (14.-5, 61.1-1.-2.31 [14.5, 61,(1,2,3 |(1,2,31(4,5,611 [[1.-2.31.14,5,61)

Answer 1

Step-by-step explanation:

The values in matrix after changeMatrix(matrix) is called will be:

[1, 2, 31]

[4, 5, 6]

The method `changeMatrix()` iterates through each element of the 2D array `matrix` and takes the absolute value of its value if the row index is odd (i.e., y is odd), and leaves it as is if the row index is even (i.e., y is even).

In the given `matrix`, the first row has an odd index of y=1, and the second row has an even index of y=0.

So when the method `changeMatrix(matrix)` is called, it takes the absolute value of the first row (-1, 2, 31) and leaves the second row (4, -5, 6) unchanged. Therefore, the resulting matrix after calling `changeMatrix(matrix)` will be:

[1, 2, 31]

[4, 5, 6]