Question

a force of 40Nis applied at the end of a wire 4m long and produces an extension of 0.24mm. if the diameter of the wire is 2.0mm. calculate the stress and strain of the wire

Answer 1

stress = 13000000 N/m or Pa

Strain = 6x10^-5

Step-by-step explanation:

Radius - d/2

Radius = 2 /2

Radius = 1 mm

Stress = F/A

stress = F / (πr^2)

Stress = 40 / (π(1 / 1000)^2)

Stress = 12732395 ≈ 13000000 N/m or Pa

Strain = Extension / Original length

Strain = (0.24 / 1000) / 4

Strain = 6x10^-5

I hope my answer helps you.