Answer:
150.5 °C
Step-by-step explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 4 L
Initial temperature (T₁) = 35 °C
Final volume (V₂) = 5.5 L
Final temperature (T₂) =?
Next, we shall convert 35 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 35 °C
Initial temperature (T₁) = 35 °C + 273
Initial temperature (T₁) = 308 K
Next, we shall determine the final (i.e the new) temperature of air. This can be obtained as follow:
Initial volume (V₁) = 4 L
Initial temperature (T₁) = 308 K
Final volume (V₂) = 5.5 L
Final temperature (T₂) =?
V₁ / T₁ = V₂ / T₂
4 / 308 = 5.5 / T₂
Cross multiply
4 × T₂ = 308 × 5.5
4 × T₂ = 1694
Divide both side by 4
T₂ = 1694 / 4
T₂ = 423.5 K
Finally, we shall convert 423.5 K to celsius temperature. This can be obtained as follow:
T(°C) = T(K) – 273
T₂ = 423.5 K
T₂ = 423.5 – 273
T₂ = 150.5 °C
Thus, the new temperature of the air is 150.5 °C