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SOLVE SYSTEM OF EQUATIONS BY THE ELIMINATION METHOD Use the Elimination Method to solve the following systems of equations.

1.
4x + 3y = 8
4x + 5y = 10
2.
3x +6y = 30
4x + 2y = 4​

User Tony Fung
by
7.3k points

1 Answer

1 vote

Answer:

1. (5/4, 1)

2. (-2, 6)

Explanation:

Question #1.

4x + 3y = 8

4x + 5y = 10

Multiply the second equation by -1 to eliminate x.

4x + 3y = 8

-1(4x + 5y = 10) = -4x - 5y = -10

4x + 3y = 8

-4x - 5y = -10

-2y = -2

Divide both sides by -2.

y = 1

Substitute y = 1 into the equation.

4x + 3y = 8

4x + 3(1) = 8

4x + 3 = 8

Subtract 3 from both sides.

4x = 5

Divide both sides by 4.

x = 5/4

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Question #2.

3x + 6y = 30

4x + 2y = 4

Multiply the second equation by -3 to eliminate y.

3x + 6y = 30

-3(4x + 2y = 4) = -12x - 6y = -12

3x + 6y = 30

-12x - 6y = -12

-9x = 18

Divide both sides by -9.

x = -2

Substitute x = -2 into the equation to find y.

3x + 6y = 30

3(-2) + 6y = 30

-6 + 6y = 30

Add 6 to both sides.

6y = 36

Divide both sides by 6 to isolate y.

y = 6

User Cassis
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7.9k points