Question

If a pump has an isentropic efficiency of 0.8, and its isentropic work is 80 kJ, determine its actual work estion 22 4 yet answered rked out of 4.00 Flag question Select one: a. 0.005 kJ b. 0.9 kJ 0 % 180 kg d. 162 kJ e. 100 kJ

Answer 1

girl i don’t do chem but i’m pretty sure If the isentropic work is 80 kJ, then the actual work can be found using the following equation:

Actual work = Isentropic work / Isentropic efficiency

Plugging in the given values, we get:

Actual work = 80 kJ / 0.8 = 100 kJ

Therefore, the actual work of the pump is 100 kJ.