Question

The initial temperature of a 1.00 liter sample of argon is 20. C. The pressure is

decreased from 720 mm Hg to 360 mm Hg and the volume increases to 2.14 liters
What was the change in temperature of the argon?

Answer 1

Therefore, the change in temperature of the argon is:

ΔT = T2 - T1 = 209 K - 20 °C = 189 K

Note that we converted the final temperature from Kelvin to Celsius by subtracting 273.15 from the Kelvin temperature.