Question

what amount of force is felt by a 10 nc charge in an electric field where there strength is 25000 n/c?

Answer 1

`\huge\boxed{\sf F = 2.5 * 10^(-4)\ N}`

Step-by-step explanation:

Given data:

Charge = q = 10 nC = 1 × 10⁻⁸ C

Electric field = E = 25000 N/C = 2.5 × 10⁴ N/C

Required:

Force = F = ?

Formula:

F = qE

Solution:

Put the given data in the above formula.

F = (1 × 10⁻⁸)(2.5 × 10⁴)

F = 2.5 × 10⁻⁴ N

`\rule[225]{225}{2}`