Question

If a=1,b=2,c=-3 find a^c+c^b-b^c​

Answer 1

Answer:1+9-(1/8)=79/8

Explanation:

a^c=1^-3=1 (1 raise to any power is always 1)

c^b=-3^2=9. As[(-3)×(-3)]=9

b^c=2^-3=1/8

Note: If the power of a number is negative the number will be reciprocal of the answer. For example if 2^3 is 8 then 2^-3 will be 1/8