Answer:
a: t = 2.21
b: 0.0165
c: we reject the null hypothesis H0: μ = 115 in favor of the alternative hypothesis Ha: μ > 115
Explanation:
a) The standardized test statistic can be calculated as:
t = (sample mean - hypothesized population mean) / (sample standard deviation / sqrt(sample size))
t = (125.7 - 115) / (29.8 / sqrt(45))
t = 2.21
b) To find the P-value, we need to find the area under the t-distribution curve to the right of the calculated t-value with degrees of freedom equal to the sample size minus one (df = 44). We can use a t-distribution table or a calculator with a t-distribution function. For example, using an online calculator with a t-distribution function, we get:
P-value = P(t > 2.21) = 0.0165 (rounded to four decimal places)
c) Since the P-value is less than the significance level α = 0.05, we reject the null hypothesis H0: μ = 115 in favor of the alternative hypothesis Ha: μ > 115. This means that we have evidence to suggest that the mean SSHA score in the population of students at the college who are at least 30 years old is higher than 115. Therefore, the teacher's suspicion that older students have better attitudes toward school is supported by the data.