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What are the roots of the equation x² + 4x - 16 = 02

(1) 2 ± 2√5
(3) 2 ± 4√5
(2) -2 ± 2√5
(4) -2 ± 4√5

User Frank Kong
by
8.4k points

1 Answer

4 votes

Hello !

x² + 4x - 16 = 0

it's a quadratic equation : ax² + bx + c

x = (-b ± √(b² - 4ac)/2a

= (-4 ± (4² - 4*1*(-16))/(2*1)

= (-4 ± √80)/2

= (-4 ± 4√5)/2

= -2 ± 2√5

User Alica
by
8.2k points
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