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How many particles are there in 65 grams of potassium iodide (KI)?

User ITukker
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2 Answers

3 votes

Answer:

0.3915597312020745

Step-by-step explanation:

User Anders Forsgren
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6 votes

Answer:

Look Down :)

Step-by-step explanation:

To determine the number of particles in 65 grams of potassium iodide (KI), we need to use the Avogadro's constant (NA) and the molar mass of KI.

The molar mass of KI can be calculated by adding the atomic masses of potassium (K) and iodine (I) in one KI molecule. The atomic masses of K and I are 39.10 g/mol and 126.90 g/mol, respectively. Therefore, the molar mass of KI is:

Molar mass of KI = atomic mass of K + atomic mass of I

= 39.10 g/mol + 126.90 g/mol

= 166.00 g/mol

Now we can calculate the number of particles in 65 grams of KI using the following formula:

Number of particles = (mass of sample / molar mass) x Avogadro's constant

Number of particles = (65 g / 166.00 g/mol) x 6.022 x 10^23 particles/mol

= 2.51 x 10^23 particles

Therefore, there are approximately 2.51 x 10^23 particles in 65 grams of potassium iodide (KI).

User Jan Katins
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