128k views
0 votes
Solve the simultaneous equations
2x+3y=2
4x+2y=5​

User Linga
by
7.8k points

2 Answers

6 votes
2x + 3y = 2
4x + 2y = 5

2x = 2 - 3y
2 * (2 - 3y) + 2y = 5

2x = 2 - 3y
4 -6y + 2y = 5

2x = 2 + 3/4 => x = 11/8
y = - 1/4

User Zachary
by
7.8k points
1 vote

Answer:x = 11/8 and y = -1/4.

Explanation:

To solve the system of simultaneous equations:

2x + 3y = 2 --- Equation (1)

4x + 2y = 5 --- Equation (2)

We can use the elimination method, which involves multiplying one or both equations by a constant so that when we add or subtract them, one of the variables is eliminated.

Multiplying Equation (1) by 2, we get:

4x + 6y = 4 --- Equation (3)

Now we can subtract Equation (2) from Equation (3):

4x + 6y = 4

(4x + 2y = 5)

4y = -1

Dividing both sides by 4, we get:

y = -1/4

Substituting y = -1/4 into Equation (1), we get:

2x + 3(-1/4) = 2

Simplifying:

2x - 3/4 = 2

2x = 2 + 3/4

2x = 8/4 + 3/4

2x = 11/4

Dividing both sides by 2:

x = 11/8

Therefore, the solution to the system of simultaneous equations is:

x = 11/8 and y = -1/4.

User Rafael Motta
by
8.4k points

No related questions found