Question

4. If y varies jointly as x and z, and y = 24, z = 2 and x = 4,

then find y when x = 12 and z = 2.

Answer 1

The answer is 72.

Explanation:

y=kxz

24=k(4)(2)

k=24/(4×2)=3

y=kxz=3(12)(2)=72