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Luke jogged 20.25 miles last week. He jogged the same distance, d, on each of 3 days. Marcus said that Luke jogged 17.25 miles on the first day since 20.25-3-d, so d = 17.25. Which explains why Marcus is wrong? The actual distance can be found using the equation 3d - 20.25, and the solution is d = 5.75. Luke jogged 5.75 miles the first day. B The actual distance can be found using the equation 3 + d-20.25, and the solution is d= 0.15. Luke jogged 0.15 mile the first day. C The actual distance can be found using the equation 3d - 20.25, and the solution is d=6.75. Luke jogged 6.75 miles the first day. D The actual distance can be found using the equation d +3=20.25, and the solution is d = 60.75. Luke jogged 60.75 miles the first day.​

User Russ Egan
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2 Answers

1 vote

Answer:

it would be The actual distance can be found using the equation 3d - 20.25, and the solution is d = 5.75. Luke jogged 5.75 miles the first day. so A

Explanation:

User PraveenP
by
8.4k points
2 votes

Answer:

Option C

Explanation:

Framing algebraic expressions and solving:

The distance jogged each day = d

The distance jogged in 3 days = 3*d = 3d

The distance jogged last week = 20.25 miles

3d = 20.25

3d - 20.5 = 0

Solution:

To find the total distance jogged on each day, we have to divide total miles (20.25) by the number of days(3).

3d = 20.25

Divide both sides by 3,

d = 20.25 ÷ 3


\boxed{\bf d = 6.75 \ miles}

User Yuriy Barvinchenko
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8.4k points