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On a standardized exam, the scores are normally distributed with a mean of 29 and a

standard deviation of 4. Find the z-score of a person who scored 34 on the exam.

User Arvanem
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2 Answers

1 vote
The solution is 0.1056
User Nathanbweb
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The z-score is a measure of how many standard deviations a data point is from the mean. It can be calculated using the formula: z = (x - μ) / σ, where x is the data point, μ is the mean and σ is the standard deviation.

In this case, the data point is the person’s score of 34, the mean is 29 and the standard deviation is 4. Plugging these values into the formula gives us: z = (34 - 29) / 4 = 5 / 4 = 1.25.

So, the z-score of a person who scored 34 on the exam is 1.25.

User GuidoS
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