Question

A lab technician needs to make 2.50 L of a 1.50 M solution of

NH4CI (molar mass = 53.5 g/mol). What mass of NH4CI is required?0.
O 0.07g
3.75g
80.3g
201.0g

Answer 1

`\huge{ \boxed{201.0 \: g}}`

Step-by-step explanation:

The mass of
`NH_4Cl` required to make the solution can be found by using the formula;

`c = (m)/(M * v)`

c is the concentration in M , mol/dm³ or mol/L

v is the volume in L or dm³

M is the molar mass in g/mol

m is the mass in grams

Making m the subject;

m = c × M × V

`m = 1.5 * 53.5 * 2.5 \\ = 200.625 \approx201.0`

We have the final answer as

201.0 g