Question

The gas constant R has the value 0.0820584 L atm K-1 mol-¹. At STP 3.2 moles of a gas weigh 57.3 g.

What is the density of the gas in g/L?

Answer 1

Step-by-step explanation:

1) Use ideal gas law to calculate liter

V = nRT/P = 0.0820584 X 3.2 X 273.15 / 1 atm = 71.726 L

2) now take grams/ liters

57.3 grams/ 71.726 L = 0.799 g/L