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Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options.

The radius of the circle is 3 units.
The center of the circle lies on the x-axis.
The center of the circle lies on the y-axis.
The standard form of the equation is (x – 1)² + y² = 3.
The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

User FatBruno
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To determine which statements are true about the circle whose equation is x^2 + y^2 - 2x - 8 = 0:

First, we can rewrite the equation in standard form by completing the square:

x^2 - 2x + y^2 = 8

(x - 1)^2 + y^2 = 9

From this form, we can see that the center of the circle is at (1, 0), which is on the x-axis. Therefore, statement 2 is true.

The radius of the circle is the square root of the constant term in the standard form equation, which is 3. Therefore, statement 1 is false and statement 5 is true.

Finally, the equation of the circle is in standard form, and we can see that the squared term for y is positive, which means that the center of the circle cannot lie on the y-axis. Therefore, statement 3 is false.

In summary, the three true statements are:

- The center of the circle lies on the x-axis.

- The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

- The standard form of the equation is (x – 1)² + y² = 3.

User Miles Henrichs
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