Question

HCl(aq) + NaHCO3(aq) → NaCl(aq) + H₂O(l) + CO₂(g)

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How many moles of CO2 will be produced if I react 300 mL
of 0.4 M HCl solution?

Answer 1

Answer: 1.333 moles CO2 correct sig figs = 1 mole

Step-by-step explanation:

1) First solve for moles HCl 2) then do stoichiometry to convert to moles CO2

1) moles = M/L = 0.4 / 0.3 = 1.333 moles HCl

2) 1.333 moles HCl X ( 1moles CO2 / 1 moles HCl) = 1.333 moles CO2