Question

What is the volume ,in milliners , of a 0.350M KOH needed to completely neutralize 15.0 ml of 0.250 M H2SO4 solutions

Answer 1

Answer: 10.7 mL

Step-by-step explanation:

this is using the dilution formula

M1V1 = M2V2 ( or in simple terms you always divide by the larger M)

V1 = M2V2 / M1

V1= 0.250 X 15.0 / 0.350 = 10.714 mL correct sig figs its 10.7 mL