What is the volume ,in milliners , of a 0.350M KOH needed to completely neutralize 15.0 ml of 0.250 M H2SO4 solutions

Question

asked Jan 26, 2024 12.7k views

1 Answer

Anirudh Rayabharam · Answer 1 · 2024-01-30T02:21:29+0000

Answer: 10.7 mL

Step-by-step explanation:

this is using the dilution formula

M1V1 = M2V2 ( or in simple terms you always divide by the larger M)

V1 = M2V2 / M1

V1= 0.250 X 15.0 / 0.350 = 10.714 mL correct sig figs its 10.7 mL